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Rate of Reaction ยป Measuring and Calculating Rates

What you'll learn this session

Study time: 30 minutes

AQA spec: 4.6.1.1

  • How to calculate the mean rate of a reaction
  • The units of rate: g/s, cm3/s and (Higher tier) mol/s
  • How to draw and read graphs of quantity against time
  • How to draw a tangent and use its slope as a measure of rate
  • Higher tier: calculating the gradient of a tangent

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What is the rate of a reaction?

Rusting is a slow reaction - it can take months, while a firework reacts in a split second

Rusting is a slow reaction - it can take months, while a firework reacts in a split second

Some reactions are slow, like iron going rusty. Some are fast, like a firework. The rate of reaction tells us how quickly a reaction happens. To find it, we measure how much reactant is used up, or how much product is made, over a period of time.

Because the rate can change as the reaction goes on, we usually work out the mean rate. This is the average rate over the whole time we measured.

The two equations

mean rate of reaction = quantity of reactant used ÷ time taken

mean rate of reaction = quantity of product formed ÷ time taken

The "quantity" can be a mass in grams (g) or a volume in cm3. A gas is often measured as a volume. A solid reactant is often measured as a mass.

Key terms:

  • Rate of reaction: how quickly reactants are used up or products are formed.
  • Mean rate: the quantity used or formed divided by the time taken.

Units of rate

The unit of rate comes from the equation. It is the unit of the quantity divided by the unit of time.

⚖ Mass

Quantity in grams and time in seconds gives a rate in g/s.

🔧 Gas volume

Quantity in cm3 and time in seconds gives a rate in cm3/s.

Higher tier only

At Higher tier you can also measure the quantity in moles. The rate is then in mol/s.

If the time is given in minutes, change it to seconds first (multiply by 60) so the unit is /s.

Calculating a mean rate

Worked example 1: a product

A reaction makes 48 cm3 of gas in 120 seconds.

Mean rate = 48 ÷ 120 = 0.40 cm3/s

Worked example 2: a reactant

A student starts with 5.0 g of a solid reactant. After 30 seconds, 2.0 g is left.

Mass used = 5.0 − 2.0 = 3.0 g

Mean rate = 3.0 ÷ 30 = 0.10 g/s

Worked example 3: moles (Higher tier only)

A reaction uses up 0.060 mol of a reactant in 40 seconds.

Mean rate = 0.060 ÷ 40 = 0.0015 mol/s

Notice that for a reactant you use the amount used up (start minus what is left), not the amount left.

Graphs of quantity against time

Collect the gas in a syringe and note the volume every 10 seconds - then plot it against time

Collect the gas in a syringe and note the volume every 10 seconds - then plot it against time

We can measure the quantity every few seconds and plot a graph. Time goes on the x-axis (the horizontal one). The quantity goes on the y-axis (the vertical one). Here is a set of results for a reaction that makes a gas:

Time (s)0102030405060
Gas made (cm3)0243846505252

To draw the graph, plot each point with a small cross, then draw a smooth curve through them. Do not join the dots with straight ruler lines.

Steep line

The reaction is fast. Lots of product forms each second.

Getting less steep

The reaction is slowing down because the reactants are being used up.

Flat line

The reaction has stopped. At least one reactant has run out.

In our results the curve is steepest at the start. In the first 10 seconds the mean rate is 24 ÷ 10 = 2.4 cm3/s. Between 20 and 30 seconds it is only 8 ÷ 10 = 0.8 cm3/s. After 50 seconds the line is flat, so the rate is zero.

A graph for a reactant going down starts high and falls. It is steepest at the start and then flattens out as the reactant is used up. The steeper the line, the faster the reaction.

You can compare two curves on the same axes. The curve that is steeper at the start, or reaches its flat part sooner, is the faster reaction.

Drawing a tangent

A mean rate is an average. But the rate at one exact moment can be different. To find it, we draw a tangent to the curve. A tangent is a straight line that just touches the curve at one point, without cutting across it. The slope of the tangent is a measure of the rate at that point.

How to draw a tangent at a chosen time:

  1. Find the chosen time on the x-axis and go up to the curve.
  2. Place a ruler so it touches the curve at that point only.
  3. Pivot the ruler until the curve is the same distance from the ruler on each side of the point.
  4. Draw a long straight line, extended well beyond the curve.

A steeper tangent means a faster rate at that time. A flat tangent means the reaction has stopped.

Key term:

  • Tangent: a straight line that touches a curve at one point, used to show the rate at that point.

Calculating the gradient of a tangent

Higher tier only

You can work out the rate at a specific time by calculating the gradient of the tangent.

gradient = change in y ÷ change in x

Worked example: A student draws a tangent at 20 s on the gas graph above. It passes through (0 s, 16 cm3) and (40 s, 60 cm3).

Change in y = 60 − 16 = 44 cm3

Change in x = 40 − 0 = 40 s

Gradient = 44 ÷ 40 = 1.1 cm3/s

So the rate at 20 s is 1.1 cm3/s. Choose two points far apart on the tangent line, not points on the curve.

For a graph that falls, the gradient is negative. We just state the size of the rate as a positive number.

Common mistakes

1. Using the amount of reactant left instead of the amount used up.

2. Leaving the time in minutes but writing the unit as /s.

3. Joining plotted points with straight lines instead of drawing a smooth curve.

4. Drawing a tangent that cuts through the curve.

5. (Higher tier) Reading the gradient from two points on the curve instead of two points on the tangent.

Exam-style question

A student reacts marble chips with acid. The reaction makes 90 cm3 of carbon dioxide in 150 seconds.

(a) Calculate the mean rate of reaction in cm3/s. (2 marks)

(b) The graph of volume against time becomes flat after 150 seconds. What does this tell you? (1 mark)

Model answer

(a) Mean rate = quantity of product formed ÷ time taken = 90 ÷ 150 = 0.60 cm3/s

(b) The reaction has stopped, because at least one reactant has been used up.

Exam tip

Write the equation first, then put the numbers in, then give the answer with its unit. The unit often earns a mark.

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