📐 Degrees mode
Your calculator must be working in degrees. Look for a small D or DEG on the display. Quick check: type sin 30. If the answer is 0.5, you are in degrees mode. If it is anything else, change the mode before you start.
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Unlock This CourseRemember, light slows down and bends towards the normal when it goes from air into glass or water. Some materials slow light more than others, so they bend it more. We need a number that says how strongly a material does this. That number is the refractive index.
Key terms:
Refractive index has no unit. It is just a number. For the materials you will meet it is always bigger than 1.
| Material | Refractive index | What it means |
|---|---|---|
| Water | about 1.33 | Slows and bends light a little |
| Glass | about 1.5 | Slows and bends light more than water |
| Diamond | about 2.4 | Slows and bends light a lot |
The exact value for glass depends on the type of glass, so a question will always give you the number or the angles you need.
In words: refractive index = sine of the angle of incidence ÷ sine of the angle of refraction.
In symbols: n = sin i / sin r
This equation is not given in the exam. You must learn it.
Why use sines and not just the angles? Look at these values for light going from air into water. Dividing the angles gives a different answer each time. Dividing the sines gives the same answer every time, and that answer is the refractive index of water.
| i in ° | r in ° | i ÷ r | sin i ÷ sin r |
|---|---|---|---|
| 20 | 14.9 | 1.34 | 1.33 |
| 40 | 28.9 | 1.38 | 1.33 |
| 60 | 40.6 | 1.48 | 1.33 |
| 80 | 47.8 | 1.67 | 1.33 |
Your calculator must be working in degrees. Look for a small D or DEG on the display. Quick check: type sin 30. If the answer is 0.5, you are in degrees mode. If it is anything else, change the mode before you start.
To turn an angle into a number, press sin, type the angle, then press =. To turn a number back into an angle, press SHIFT (or 2nd), then sin, type the number, then press =. Use sin−1 whenever the question asks for an angle.
You can rearrange the equation in two ways:
| To find | Use | Then |
|---|---|---|
| Refractive index | n = sin i ÷ sin r | Done. No unit |
| Angle of refraction | sin r = sin i ÷ n | Use sin−1 to get r |
| Angle of incidence | sin i = n × sin r | Use sin−1 to get i |
Question: A ray of light goes from air into a clear block. The angle of incidence is 50° and the angle of refraction is 30°. Calculate the refractive index of the block.
n = sin i / sin r
n = sin 50° ÷ sin 30°
n = 0.7660 ÷ 0.5
n = 1.53 (no unit)
Question: A ray of light from a torch hits the surface of a pond at an angle of incidence of 45°. The refractive index of water is 1.33. Calculate the angle of refraction.
n = sin i / sin r, so sin r = sin i ÷ n
sin r = sin 45° ÷ 1.33
sin r = 0.7071 ÷ 1.33 = 0.5317
r = sin−1 0.5317
r = 32°
Check: 32° is smaller than 45°, as it should be for light going into water.
Question: Light goes from air into a glass window of refractive index 1.5. The angle of refraction in the glass is 20°. Calculate the angle of incidence.
n = sin i / sin r, so sin i = n × sin r
sin i = 1.5 × sin 20°
sin i = 1.5 × 0.3420 = 0.5130
i = sin−1 0.5130
i = 31°
Question: A ray of light inside a glass block of refractive index 1.5 meets the surface at 30° to the normal and comes out into the air. Calculate the angle between the ray in the air and the normal.
The sine of the angle in the air always goes on top of the equation, whichever way the light is travelling. For a ray coming out of glass, a question will call the 30° in the glass the angle of incidence and the angle in the air the angle of refraction. The names swap, but the angle in the air still goes on top.
n = sin (angle in air) ÷ sin (angle in glass), so sin (angle in air) = n × sin (angle in glass)
sin (angle in air) = 1.5 × sin 30° = 1.5 × 0.5 = 0.75
angle in air = sin−1 0.75
angle in air = 49°
Check: the angle in the air is bigger than the angle in the glass, because the ray bends away from the normal as it comes out.
Send the same ray, at an angle of incidence of 45°, into three different materials. The equation gives these angles of refraction.
r = 32°. The ray is bent the least.
r = 28°. The ray is bent more, so it ends up closer to the normal.
r = 17°. The ray is bent the most.
So for the same angle of incidence, a bigger refractive index gives a smaller angle of refraction.
A ray of light travels from air into a block of clear plastic. The angle of incidence is 55° and the angle of refraction is 34°.
(a) State the equation linking refractive index, angle of incidence and angle of refraction. [1 mark]
(b) Calculate the refractive index of the plastic. [2 marks]
(c) A second ray meets the same block at an angle of incidence of 30°. Calculate the angle of refraction for this ray. [3 marks]
(d) The plastic block is replaced by a block of diamond, which has a larger refractive index. The angle of incidence is still 30°. State and explain how the angle of refraction changes. [2 marks]
(a) n = sin i / sin r (1)
(b) n = sin 55° ÷ sin 34° = 0.8192 ÷ 0.5592 (1)
n = 1.46 (1) (1.5 also gains the mark; no unit)
(c) sin r = sin i ÷ n = sin 30° ÷ 1.46 (1)
sin r = 0.5 ÷ 1.46 = 0.3425 (1)
r = sin−1 0.3425 = 20° (1)
(d) The angle of refraction is smaller (1), because a material with a larger refractive index slows the light more and so bends it more towards the normal (1).
In part (c), write down the value of sin r before you press sin−1. If you slip on the last step, the examiner can still give you the marks for the substitution and the rearrangement.