🎵 Tuning fork
Simple, and its frequency is marked on it, so you can check your answer. But the sound is quiet and fades in a few seconds, so the trace shrinks while you are reading it.
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In Oscilloscopes, Pitch and Loudness you saw that more waves across the screen means a higher frequency. This practical goes one step further: you use the trace to measure the frequency in hertz.
The plan is simple. Time runs across the oscilloscope screen, so the width of one complete wave tells you the time period of the sound. Once you have the time period, the frequency comes from frequency = 1 / time period.
Key terms:
You need a microphone connected by a cable to the input of an oscilloscope, and a source of a steady, pure note. There are two common choices.
Simple, and its frequency is marked on it, so you can check your answer. But the sound is quiet and fades in a few seconds, so the trace shrinks while you are reading it.
The note stays the same for as long as you like, so the trace stays steady. You can also change the frequency with the dial and test several notes.
To draw the apparatus in the exam, draw the source on the left (a loudspeaker joined to a box labelled 'signal generator', or a tuning fork). Draw a microphone a short distance in front of it. Then draw a wire from the microphone to a box with a screen, labelled 'oscilloscope'.
Why adjust the settings? If the waves are squashed together or the trace is tiny, you cannot read the divisions accurately. A tall trace with a few wide waves is the easiest to measure.
There are two steps.
Step 1: time period = number of divisions for one complete wave × time base setting
Step 2: frequency = 1 / time period, f = 1 / T
Remember, f = 1 / T is given on the formulae page, and it only gives hertz if the time period is in seconds. Time base settings are usually in milliseconds, so divide by 1000 before step 2.
A signal generator and loudspeaker produce a note. On the oscilloscope, one complete wave is 8 divisions wide. The time base is set to 0.2 ms/div. Calculate the frequency.
time period = number of divisions × time base = 8 × 0.2 = 1.6 ms
1.6 ms = 1.6 ÷ 1000 = 0.0016 s
f = 1 / T = 1 ÷ 0.0016 = 625 Hz
You can only read the screen to about the nearest 0.1 of a division. If one wave is only 2 divisions wide, an error of 0.1 of a division is a large fraction of your reading. If you measure across several waves instead, the same small reading error is shared out between all of them, so the error in the time for one wave is much smaller.
Count carefully. From the first crest to the sixth crest is 5 complete waves, not 6. Call the first crest zero.
A tuning fork is marked 256 Hz. On the frozen trace, 5 complete waves take up 9.8 divisions. The time base is set to 2 ms/div. Calculate the frequency.
time for 5 waves = 9.8 × 2 = 19.6 ms
time period = 19.6 ÷ 5 = 3.92 ms = 0.00392 s
f = 1 / T = 1 ÷ 0.00392 = 255 Hz (to 3 significant figures)
This is very close to the 256 Hz marked on the fork, so the measurement is accurate.
Compare this with using one wave. A single wave looks about 2.0 divisions wide, which gives T = 4.0 ms and f = 250 Hz. Measuring across 5 waves gives the better answer.
With a signal generator you can test several notes and compare each answer with the dial. You change the time base each time so that a few waves fill the screen.
| Frequency on the dial in Hz | Time base in ms/div | Divisions for one wave | Time period in ms | Measured frequency in Hz |
|---|---|---|---|---|
| 125 | 2 | 4.0 | 8.0 | 125 |
| 320 | 1 | 3.1 | 3.1 | 323 |
| 800 | 0.5 | 2.5 | 1.25 | 800 |
| 1000 | 0.2 | 5.1 | 1.02 | 980 |
The measured values are close to the dial values but not always exactly the same. Small differences come from reading the divisions on the screen, and the dial on the signal generator may not be perfectly accurate either.
Variables: when you test several notes, the frequency set on the signal generator is the independent variable. The time period measured from the trace is the dependent variable. Keep the same microphone, loudspeaker and oscilloscope throughout.
Safety: this is a low-risk practical. Keep the loudspeaker at a comfortable volume to protect your hearing. Strike the tuning fork on a cork or rubber block, never on a hard bench or near your eyes. The equipment runs from the mains, so keep liquids away and cables tidy.
Forgetting to change milliseconds into seconds. Using T = 1.6 instead of 0.0016 gives a frequency that is 1000 times too small.
Measuring from a crest to the next trough. That is only half a wave. One complete wave is crest to crest.
Using the gain setting in the calculation. The gain is about the height of the trace. Only the time base is used to find the time period.
Counting crests instead of waves. Six crests in a row mark out five complete waves.
Leaving noise in the room. Other sounds reach the microphone and make the trace uneven, so work in a quiet room with the source close to the microphone.
A student investigates the frequency of the sound from a tuning fork. She holds the vibrating fork near a microphone connected to an oscilloscope.
The trace shows 4 complete waves in 7.8 divisions across the screen. The time base setting is 1 ms/div.
(a) Describe how the student should adjust the oscilloscope to obtain a trace that is easy to measure. [2 marks]
(b) Calculate the frequency of the sound. Give your answer to 3 significant figures. [4 marks]
(c) Explain why the student measured across 4 waves instead of 1 wave. [2 marks]
(d) The tuning fork is marked 512 Hz. Comment on the student's result. [1 mark]
(e) Suggest one advantage of using a signal generator and loudspeaker instead of the tuning fork. [1 mark]
(a) Adjust the gain so the trace is tall but still fits on the screen (1). Adjust the time base so the trace is steady and shows a few complete waves (1).
(b) time for 4 waves = 7.8 × 1 = 7.8 ms (1). time period = 7.8 ÷ 4 = 1.95 ms (1) = 0.00195 s (1). f = 1 / T = 1 ÷ 0.00195 = 513 Hz (1).
(c) The screen can only be read to a fraction of a division, and this reading error is shared between 4 waves (1), so the error in the time period of one wave is smaller and the frequency is more accurate (1).
(d) The result is accurate, because 513 Hz is very close to the 512 Hz marked on the fork (1).
(e) Any one from: the sound does not fade, so the trace stays steady; the note is louder, so the trace is taller; the frequency can be changed to test other notes (1).
Set the calculation out in three lines every time: divisions × time base, then milliseconds to seconds, then f = 1 / T. The examiner gives marks for each line, so you still score if a slip on the calculator spoils the final answer.